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JsonElement e4 = new JsonPrimitive(json2) If it cant be parsed, its considered to be just a string to be compared.
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If the value can be parsed as valid JSON, its parsed so. Conversion to Json Primitive for comparison JsonElement e3 = new JsonPrimitive(json1) JsonUnit tries to be clever when parsing the expected value. Conversion to JsonTree for comparison Gson gson = new GsonBuilder().create()
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(You could also convert your Java object into a JSONObject but I find that it’s much easier to convert it into a string. First, you have to convert your Java object into a JSON string (using Jackson, for example) and then compare it with your expected JSON string using JSONassert. JsonObject obj1 = (JsonObject) parser1.parse(json2) A useful library for comparing JSON objects is JSONassert. JsonObject obj = (JsonObject) parser.parse(json1) When comparing JUnit and AssertJ you can also consider the. So my test class consists of a few Java methods, and what is essentially a list of JSON files to process. When using indefinite JSON Paths you must assert the value due.
#Junit json compare Patch
My testRunner() method (no relation to JUnit test runners) reads that JSON file, processes it, and asserts that the test passed. Also, if patch will return dictionary object, it will be converted to string before comparison. Conversion to JsonObejct for comparison JsonParser parser = new JsonParser() The compareToIgnoreCase() method compares two strings lexicographically, ignoring lower case and upper case differences. The AHTest039.json file is the actual test. The methods of comparison are as follows:Īssuming that we have ID and name in our map, we have the following two possibilities after converting it into json: String json1 = "" 1. When we compare the two jsons, we need to ignore their order of comparison. When map data is converted to json, JSON output is out of order because map is out of order. Gson – Compare two order-independent JSON strings